Mar 13, 2006 · Well, there's good news. It isn't a complicated problem, because the velocity of the cars after the collision has to be the same as the velocity of the center of mass of the two-car system immediately before the collision.

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Figure 3.11 (Example 3.2) (a) Graphical method for finding the resulS S S tant displacement vector R 5 A 1 B. (b) Adding the vectors in reverse S S S order 1B 1 A 2 gives the same result for R. Analyze In this example, we show two ways to analyze the problem of finding the resultant of two vectors.

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If the shopping bag weighs 1 kilogram and the shopping bag is rotated in a vertical circle of radius 0.1 meters and the shopping bag is moving at 2.5 m/s at the bottom of the circle, how fast is ...

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Nov 13, 2016 · The time will be the same for both cars. The cars will cover different distances because they are travelling at different speeds. #D = S xx T# The distance travelled by the slower car = #50xx x# miles. The distance travelled by the faster car = #58xx x# miles. The two distances differ by 40 miles. #58x - 50x= 40# #8x =40# #x = 5# hours

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The fundamental problem is that, as you've realized, multiplying the acceleration by the direction is wrong. This is because your "direction" is not just the direction the car is accelerating; it's the direction the car is moving. The easiest way to straighten this out is to start by considering acceleration and steering separately.

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Two cars are traveling in the same direction along the same route. The red car travels at a constant speed of 40 miles per hour, and the black car is traveling at a constant speed of 50 miles per hour. If the red car is 20 miles ahead of the black car, how many hours will it take the black car to overtake the red car? A. 0.1 B. 0.6 C. 1 D. 1.2 E. 2